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(y+3)(y^2-3y+9 what is the product?
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(y+3)(y^2-3y+9 what is the product?

User Naveed Ahmed
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1 Answer

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=(y+3)(y^2+−3y+9)
=(y)(y^2)+(y)(−3y)+(y)(9)+(3)(y^2)+(3)(−3y)+(3)(9)
=y^3−3y^2+9y+3y^2−9y+27
Answer:
=y3+27
User NatKSS
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