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DE is a midsegment of AABC . Find the value of x .
B
х
5
А

DE is a midsegment of AABC . Find the value of x . B х 5 А-example-1

1 Answer

9 votes

Answer:

x = 10

Explanation:

DE is the midsegment joining the midpoints of BC and AC respectively.

Therefore, by the property of midsegment of a triangle,

DE will be parallel and half of the measure of the third side of the triangle.

DE =
(1)/(2)(AB)

5 =
(x)/(2)

x = 10 units

User Yahavi
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