Question

Not only answer,but also the processes.Please

Answer 1

`(3)/(x^2-7x+10)+2= (x-4)/(x-5)`
if we factor (x²-7x+10) we get (x-5)(x-2)
multiply bot sides by (x-5)(x-2)
3=(x-4)(x-2)
3=x²-6x+8
minus 3 both sides
0=x²-6x+5
what 2 numbers multily to 5 and add to -6?
-5 and -1
0=(x-1)(x-5)
set to zero
x-1=0
x=1

x-5=0
x=5

x=1 and 5

Answer 2

The value of x is either 3 or 5