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Find an angle T on the unit circle such that 90°< T < 360°, tan T = tanU and m∠U = 50°.

User Akshay Rao
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1 Answer

5 votes
okay for this, I'm pretty sure we have to use All Students Take Calc. By this, tangent is positive in quadrants 1 and 3. However, with the restriction given, it has to be Q3. For an angle in quadrant 3, you use 180°+x. In this case, x=50°.
Angle T=180°+50°=230°.
User Minsky
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