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If the radius of the Earth is roughly 3,960 miles, how many times larger is the volume of the Earth than the volume of a ping-pong ball? A ping-pong ball has a radius of 0.7441 inches. 1 mile = 5,280 feet.

User MMalke
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Final answer:

The volume of the Earth is approximately 1.083 x 10^21 times larger than the volume of a ping-pong ball.

Step-by-step explanation:

To find the ratio of the volumes, we need to compare the volume of the Earth to the volume of a ping-pong ball. The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius.

For the Earth, the radius is 3,960 miles. Converting this to inches, we get 3,960 miles × 5,280 feet/mile × 12 inches/foot = 251,136,000 inches.

For the ping-pong ball, the radius is 0.7441 inches. Substituting the values into the volume formula, we get:

Volume of Earth = (4/3)π(251,136,000)^3

Volume of ping-pong ball = (4/3)π(0.7441)^3

Therefore, the volume of the Earth is:

Volume of Earth/Volume of ping-pong ball = [(4/3)π(251,136,000)^3] / [(4/3)π(0.7441)^3]

After simplifying and canceling out terms, we get:

Volume of Earth/Volume of ping-pong ball = (251,136,000)^3 / (0.7441)^3

Calculating this expression gives approximately 1.083 × 10^21. So, the volume of the Earth is about 1.083 × 10^21 times larger than the volume of a ping-pong ball.

User Anubhab
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The volume of the Earth is 2.21865*10²² times larger than the volume of a ping-pong ball
User Arnaud SmartFun
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