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What values of b satisfy 3(2b + 3)^2 = 36?

User Chamnap
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1 Answer

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3(2b + 3)² = 36

Divide both sides by 3.

3(2b + 3)² / 3 = 36/3

(2b + 3)² = 12

Take the square root of both sides.

√(2b + 3)² = √12

(2b +3) = +√12 or -√12

Solving when:

2b + 3 = +√12 2b + 3 = -√12

2b = √12 - 3 2b = -√12 - 3

b = (√12 - 3)/2 √12 ≈ 3.46 b = (-√12 - 3)/2

b ≈ (3.46 - 3)/2 b ≈ (-3.46 - 3)/2

b ≈ 0.46/2 b ≈ -6.46/2

b ≈ 0.23 b ≈ -3.23

Therefore b ≈ 0.23 or -3.23

Hope this helps.
User Shan Kulkarni
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