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How to do question 27

How to do question 27-example-1
User Talnicolas
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1 Answer

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1/(sin(90 + θ)cos(360 - θ)) - tan²(-θ)

Note:

sin(90 + θ) = cosθ Cosine and Sine are complementary.

cos(360 - θ) = cosθ Cosine positive in 4th quadrant.

tan(-θ) = -tanθ Negative angle concept.


1/(sin(90 + θ)cos(360 - θ)) - tan²(-θ) = 1/(cosθcosθ) - (-tanθ)²

= 1/(cos²θ) - tan²θ

= (1/cosθ)² - tan²θ
Note: 1/cosθ = secθ

= (secθ)² - tan²θ

= sec²θ - tan²θ

= 1


Note that 1+ tan²θ = sec²θ is a Trigonometric identity.

That means: sec²θ - tan²θ = 1

Hope this explains it.
User AreusAstarte
by
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