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Help pls! Complex numbers :sin(2+3i).......Function Values Compute ( in the form u + iv).?

Help pls! Complex numbers :sin(2+3i).......Function Values Compute ( in the form u + iv).?
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Help pls! Complex numbers :sin(2+3i).......Function Values Compute ( in the form u + iv).?

User Daynesha
by
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1 Answer

6 votes
sin(a+bi) = sina·coshb + i·cosa·sinhb
sin(2+3i) = sin2·cosh3 + i·cos2·sinh3
so
u = sin2cosh3
v = cos2sinh3
User Chrysa
by
8.1k points
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