Question

Question 3 (1 point)

Consider the following unbalanced chemical equation representing the combustion of methane, yielding carbon dioxide and water.
CH4 + O2 --> CO2 + H20
If you had burned 800 g of methane, how many moles of Carbon dioxide would be produced?

A)122.22
B)8
C)2200
D)100
E)670

F)750
G)50

Answer 1

Im pretty sure its B

Step-by-step explanation:

Answer 2

G) 50 mol

Step-by-step explanation:

Given data:

Mass of methane = 800 g

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 800 g/ 16 g/mol

Number of moles = 50 mol

Now we will compare the moles of methane and carbon dioxide.

CH₄ : CO₂

1 : 1

50 : 50