Question

From a survey, a reporter determined that the true estimate for the proportion of citizens who plan to sign a petition is between 68% and 74%. What is the survey’s margin of error?

Answer 1

±3% this was the answer from my test

Answer 2

Therefore, the survey's margin of error is ±3%

Explanation:

From a survey, a reporter determined that true estimate for the proportion of citizens who plan to sign a petition is between 68% and 74%.

given estimate range = 68% to 74%

Margin of error = (74% - 68%) ÷ 2

6 ÷ 2 = 3%

Therefore, the survey's margin of error is ±3%