Question

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. What is the acceleration of the crate?

Answer 1

We have: Fnet = m×a
Here, Fnet = 1860-480 = 1380 towards right
m = 230 Kg

Substitute their values into the expression:
1380 = 230 × a
a = 1380 / 230
a = 6 m/s² towards right

In short, Your Answer would be 6 m/s² towards right

Hope this helps!