Answer:
The probability that Emma has heart disease and the test predicts heart disease is:
48%
Explanation:
Let A denote the event that Emma has a heart disease.
and B denote the event that the test predicts accurate.
Hence, A∩B denote the event that Emma has heart disease and the test predicts heart disease.
From the given equation we have:
P(A)=0.6
and P(B)=80%=0.8
As we know that event A and event B are independent.
Hence, we have:
P(A∩B)=P(A)×P(B)
⇒ P(A∩B)=0.6×0.8
⇒ P(A∩B)=0.48=48%
Hence, the probability is:
48%