Question

(1) Find the area of minor sector AOB

(2) Find the perimeter of the circle​

Answer 1

to find answers we first need the radius , in this case we find it using arc length

arc length =
`(115)/(360)*2\pi r`

18.07=
`(115)/(360)*2\pi r`

18.07=
`(230\pi r)/(360)`

18.07x360=
`230\pi r`

r=
`(18.07*360)/(230\pi )`

r=9cm

1) area of minor sector=
`(115)/(360)*\pi r^(2)`

=
`(115)/(360)*\pi* 9^(2)`

= 81.29
`cm^(2)`

2) perimeter of the circle is the same as its circumference which is
`2\pi r`

circumference=
`2\pi r`

=
`2*\pi *9`

=56.55cm

Explanation: