Question

Find an equation of the line passing through the point (6;5) and perpendicular to the line whose equation is 2y + 3x = 6.

Answer 1

Search ResultsFirst, put the equation of the line given into slope-intercept form by solving for y. You get y = 2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

Answer 2

2y + 3x = 6.
2y = -3x + 6
y = -3/2x + 3
...slope = -3/2

because perpendicular so slope = 2/3

using y = mx + b passing (6;5) to find b
5 = 2/3(6) + b
5 = 4 + b
5 - 4 = b
1 = b or b = 1

Answer:
Equation: y = 2/3x + 1