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What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0
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What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0

User Mschmidt
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x + 9 = 2(x - 1)^2
x + 9 = 2(x^2 - 2x + 1)
x + 9 = 2x^2 - 4x + 2
2x^2 - 4x + 2 - x - 9 = 0
2x^2 - 5x -7 =0
User Mike Gardner
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