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How many arrangements of 3 digits can be formed from the digits 0 through 9?

User Juandopazo
by
5.8k points

2 Answers

7 votes

Answer:

The required number of arrangements = 900

Explanation:

Digits through which the number is to be formed : 0, 1, 2, 3, 4, ......9

Total number of digits available to form the number = 10

Now, No. of digits in the number which is to be formed = 3

So, number of choices available for 1st digit = 9 (0 will not be included)

Number of choices available for 2nd digit = 10

Number of choices available for 3rd digit = 10

So, Total number of arrangements of 3 digits which can be formed from the digits 0 to 9 = 10 × 10 × 9

= 900

Therefore, The required number of arrangements = 900

User Anchit Mittal
by
6.1k points
4 votes

Answer: The required number of arrangements is 1000.

Step-by-step explanation: We are given to find the number of arrangements of 3 digits that can be formed from the digits 0 to 9.

Since we are talking about the 3 digit arrangements, not the 3 digit numbers,

so we have 10 options 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 for each of the three places in the arrangement.

Therefore, the number of 3 digit arrangements that can be formed is given by


n=10* 10* 10=1000.

Thus, the required number of arrangements is 1000.

User Rohan Grover
by
6.5k points