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What is an equation of the line that passes through the point (6,1)(6,1) and is parallel to the line x+3y=15

User AlwaysNeedingHelp
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2.5k points

1 Answer

21 votes
21 votes

Answer:

Explanation:

Let's write everything in slope-intercept format of y=mx+b, where m is the slope and b is the y-intercept.

x+3y=15

3y= -x + 15

y = (-1/3)x + 5

Parallel lines will have the sam slope, in this case -(1/3), So the new line will be:

y = (-1/3)x + b

We need to fijnd a value of b that will force the ine through point (6,1). Enter (6,1) in the equation and solve for b:

y = (-1/3)x + b

1 = (-1/3)(6) + b

1 = (-2) + b

b = 3

The parallel line is:

y = (-1/3)x + 3

See the attached graph.

What is an equation of the line that passes through the point (6,1)(6,1) and is parallel-example-1
User Vromanch
by
3.1k points
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