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Work out the size angles x,y and z​

Work out the size angles x,y and z​-example-1
User Denesha
by
3.4k points

2 Answers

12 votes

The values of x, y, and z are
64 degrees,
64 degrees, and
20 degrees respectively.

In the given figure we can see that triangle ABD is an isosceles triangle.

This means that the angles x and y will be equal to each other.

Therefore we can calculate x and y as:


52 + x + y = 180 (using the property of the sum of all angles in a triangle)

Substitute y with x because they are equal:


52 + x + x = 180\\52 + 2x = 180\\2x = 180 - 52\\x = 128 / 2\\x = 64

Since x = y, thus, y is also equal to
64.

Now we will calculate z:
Angle ADC is making a linear pair with y.

Therefore,
ADC + y = 180\\ADC = 180 - 64\\ADC = 116


ADC + z + 44 = 180 (sum of all angles in a triangle)


116 + z + 44 = 180\\z = 180 - 116 - 44\\z = 180 - 160\\z = 20

User Bhavnik
by
4.2k points
1 vote

Answer:

x = y = 14

z = 70

Explanation:

As we can see from the markings, x = y

So we have an isosceles triangle in ABD

the sum of angles in a triangle is 180

52 + x + y = 180

x + y = 180-52

x + y = 28

so since x = y

x = y = 14

To get z, we have that;

52 + z + 14 + 44 = 180

z + 110 = 180

z = 180-110

z = 70

User Genee
by
4.3k points