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Write (3 − 7i) − (-11 + 5i) as a complex number in standard form. A) 14 − 12i b) 14 + 12i c) 10 − 6i d) 14 − 2i

Write (3 − 7i) − (-11 + 5i) as a complex number in standard form. A) 14 − 12i b) 14 + 12i c) 10 − 6i d) 14 − 2i
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Write (3 − 7i) − (-11 + 5i) as a complex number in standard form.

A) 14 − 12i
b) 14 + 12i
c) 10 − 6i
d) 14 − 2i

User Guan Boshen
by
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2 Answers

7 votes
i believe its 10-6i im pretty sure
User Andrew Mao
by
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5 votes
It's A because you flip the signs on both terms in the second set if parentheses and then just add
User Setomidor
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