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Find the equation of the line passing through point (3,5) and with slope = 1/3

a) y=1/3x+4
b) y=-1/3x+4
c) y=3x-5
d) y=1/3x+5

User Bogardon
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1 Answer

2 votes

Answer:

A. y = 1/3 x + 4

Explanation:

The standard form of equation of a line in point slope form is expresses as

y - y0 = m(x-x0)

m is the slope

(x0, y0) is a point on the line

Given

m = 1/3

(x0, y0) = (3, 5)

Substitute into the equation

y - 5 = 1/3 (x-3)

3(y-5) - x-3

3y - 15 = x-3

3y = x-3+15

3y = x+12

y = 1/2 x + 12/2

y = 1/3 x + 4

Hence the require equation of the line is y = 1/3 x + 4

User Achtung
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3.2k points