66.2k views
1 vote
A valet has 34 cars to park in a rectangular array, what are tge different ways the valet could park the cars

2 Answers

4 votes

Final answer:

The student is asking about the possible rectangular arrays for parking 34 cars. There are two ways to park the cars, either in a 1 x 34 or a 2 x 17 formation. The exact probability of at least 10 of 22 cars being parked crookedly cannot be determined with the given information.

Step-by-step explanation:

The student's question relates to mathematics and involves determining the different ways a valet could park 34 cars in a rectangular array. To solve this, we need to find the divisors of 34, which represent the dimensions of possible rectangular arrays. The number 34 is the product of the prime numbers 2 and 17, so the possible dimensions for parking the cars are 1 x 34 or 2 x 17. Therefore, the valet has two different ways to arrange the cars in a rectangular array.

For the provided exercises:

  1. For every 22 cars, approximately 8.25 are parked crookedly since 37.5% of 22 is 8.25 (Option A).
  2. The probability of at least 10 of the 22 cars being parked crookedly would require more information or a probability distribution to calculate accurately, which is not given in the provided information.

User DarkCrow
by
5.8k points
7 votes
17 by 2 because 34 divided by 2 is 17
User Ola M
by
5.9k points