Question

That 1.5kg hawk is now soaring at 20m/s. What is the hawk’s kinetic energy? Show your work and include all units.

Answer 1

Kinetic energy = (1/2) x (mass) x (speed)²

= (1/2) x (1.5 kg) x (20 m/s)²

= (0.75 kg) x (400 m²/s²)

= 300 joules

Answer 2

Answer: KE = (1/2) × (1.5 kg) × (20 m/s)² = 300 J

Explanation:

The 1.5kg hawk is now soaring at 20m/s. What is the hawks Kinetic Energy?

a. Step 1: Formula KE=½ × M × V²

b. Step 2: Data m = 1.5 kg, v = 20 m/s

c. Step 3: plot data into formula KE= ½ × 1.5 × 20²

d. Step 4: Solve

KE = (1/2) × (1.5 kg) × (20 m/s)² = 300 Joules

or

KE = (1/2) × (1.5 kg) × (20 m/s)² = 300 J