Question

Solve this problem find four consecutive intergers whos sum is 114 written out

Answer 1

If
`x` is one of the component integers, then the next consecutive integer is
`x+1`, the following one is
`x+2` and so on.

This means the sum can be written as

`x+(x+1)+(x+2)+(x+3)=114`

Solving for
`x`, you find that
`x=27`, so the integers are
`27,28,29,30`.