Question

Charles Law

A balloon of helium was put in the freezer at -23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) HELP ASAP

A. 1.4
B. 45000
C. 4.5
D. 0.22

Answer 1

The answer can't be A because it is the amount in liters and D is less than the average B only gives the full value non right of the decimal so the answer is C

Answer 2

Answer : The volume at
`177^oC` will be, (C) 4.5 L

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T`

or,

`(V_1)/(V_2)=(T_1)/(T_2)`

where,

`V_1` = initial volume of gas = 2.5 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`-23^oC=273+(-23)=250K`

`T_2` = final temperature of gas =
`177^oC=273+177=450K`

Now put all the given values in the above formula, we get the final volume of the gas.

`(2.5L)/(V_2)=(250K)/(450K)`

`V_2=4.5L`

Therefore, the volume at
`177^oC` will be, (C) 4.5 L