Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of 2 in each case.

asked Feb 20, 2018 115k views

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Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of

2 in each case.

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12=2*2*3
45=3*3*5
15=3*5
10=2*5
L.C.M=2*2*3*3*5=180
required number 180+2=182

Eli Berkow answered Feb 24, 2018

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