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What is the limit of the absolute value of (x-2) divided by (x-2) as x approaches 2-

1 Answer

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\lim_(x \to \infty) (|x-2|)/(x-2)
as approaches 2-
that '-' after the 2 means as it approaches from the left
ok
from the left, it is like from 1 to 2
as it approaches from the left, it is
(-1(x-2))/(x-2)
it is negative since when the value of x is smaller than 2, the value of x-2 is negative so then the absolute value is making it positive, to do that, we multiply it by -1
therefor

(-1(x-2))/(x-2) or -1

it approaches -1
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