Question

Determine the percent composition of chlorine (Cl) in sodium chloride (NaCl). .

Answer 1

It's (grams-of-Cl/total-grams)(100), so (35.45g/58.44g)(100) = 60.66% Cl. Hope this helps!

Answer 2

`\% Cl=61.65\%`

Step-by-step explanation:

Hello,

In this case, chlorine's percent composition is given by the shown below formula:

`\% Cl=(n_(Cl)m_(Cl))/(M_(NaCl))*100\%`

Whereas
`n_(Cl)` accounts for the number of chlorine atoms into the NaCl,
`m_(Cl)` for chlorine's atomic mass and
`M_(NaCl)` for sodium chloride's molar mass, therefore, the percent composition of chlorine turns out:

`\% Cl=(1*35.45)/(58.45)*100\%=61.65\%`

Best regards.