Question

HELP ASPAPP The general form of an equation is x2+y2−25x+3y+1=0.

What is the equation of the circle in standard form?

Answer 1

Answer: Choice A (May vary from test to test)

Explanation:

(x-1/5)^2 + (y+3/2)^2 = 129/100

Just an FYI:

I can't stress this enough... Add equation symbols when applicable, for example: √,^,/, etc. You can't expect to have someone give the correct answer when you literally typed the equation out incorrectly.

Answer 2

the first (top) answer option. ... = 129/100

Explanation:

the for me qualifying or disqualifying term is the constant term as the product and sum of all the constant parts.

the general form has the constant parts

... + 1 = 0

so, all the constant terms from the squares on the left side minus the constant term on the right side must be 1.

let's start from the bottom : the 4th answer option.

the constant parts are

... + (-1/5)² + ... + (3/2)² = 121/100

... + 1/25 + ... + 9/4 = 121/100

... + 0.04 + ... + 2.25 = 1.21

... + 2.29 - 1.21 = ... + 1.08

and NOT 1. so, this is wrong.

the 3rd answer option.

... + (-1/3)² + ... + (-3/2)² = 221/100

... + 1/9 + ... + 9/4 = 221/100

... + 0.111111... + ... + 2.25 = 2.21

... + 0.111111... + ... + 2.25 - 2.21 = 0

... + 0.111111... + ... + 0.04 = 0

... + 0.111111 + 0.04 = 0.15111111...

and NOT 1. so, this is wrong.

the 2nd answer option.

... + (-1/5)² + ... + (3/2)² = 229/100

... + 1/25 + ... + 9/4 = 229/100

... + 0.04 + ... + 2.25 = 2.29

... + 2.29 - 2.28 = ... + 0

and NOT 1. so, this is wrong.

the first answer option.

... + (-1/5)² + ... + (3/2)² = 129/100

... + 1/25 + ... + 9/4 = 129/100

... + 0.04 + ... + 2.25 = 1.29

... + 2.29 - 1.29 = ... + 1

this IS 1. so, this is correct.

this corresponds now to the original

... + 1 = 0