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Suppose an investment of $3,800 doubles in value every decade. The function f(x) = 3,800 * 2^2 gives the value of the investment after x decades. How much is the investment worth after 2 decades? A. $152,
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Feb 14, 2018
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Suppose an investment of $3,800 doubles in value every decade. The function f(x) = 3,800 * 2^2 gives the value of the investment after x decades. How much is the investment worth after 2 decades?
A. $152,000
B. $15,200
C. $76,000
D. $7,600
Mathematics
high-school
Yag
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Yag
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doubles every decade
basically
for x deckades
the amount is multiplied by 2^x
so
2decades
2^2
3800*2^2
3800*4
15200
B is answer
Rick Minerich
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Feb 16, 2018
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Rick Minerich
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3
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3,800 x 4 = 15,200 therefore:
B
Heyjii
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Feb 20, 2018
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Heyjii
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