Question

Find the equation for the line that passes through the point (−4,−2), and that is perpendicular to the line with the equation y−1=34(x+2).

Answer 1

Find the equation for the line that passes through the point (−4,−2), and that is perpendicular to the line with the equation y−1=34(x+2).

Answer 2

Find the equation for the line that passes through the point (−4,−2), and that is perpendicular to the line with the equation y−1=34(x+2).
y−1=34(x+2)
the equation above can be written in the form of y=ax+b, as follows:
y-1=34x+68
y=34x+69
the slope of the line is a=34
the slope of the perpendicular line will be:
m=-1/34
thus the equation of the perpendicular line cutting through (-4,-2) will be:
m(x-x1)=y-y1
thus
-1/34(x-(-4))=y-(-2)
-1/34x-4/34=y+2
y=-1/34x-36/17
Answer: y=-1/34x-36/17