Question

Use the graph below to answer the question that follows: cosine graph with points at 0, 3 and pi, negative 5 and 2 pi, 3 What are the amplitude, period, and midline of the function?

Amplitude: 4; period: 2π; midline: y = −1
Amplitude: 8; period: 2π; midline: y = 1
Amplitude: 8; period: π; midline: y = −1
Amplitude: 4; period: π; midline: y = 1

Answer 1

For this case the amplitude is given by:
A = (l-5l + 3) / 2
A = 8/2
A = 4
The middle line is given by:
y = -1
The period of the function is given by:
T = l x2 - x1 l
T = l 0 - 2pi l
T = l - 2pi l
T = 2pi
Answer:
Amplitude: 4; period: 2π; midline: y = -1