Question

Whats the equation of the line that passes through (3,8) and (6,0)

Answer 1

EQUATION OF A LINE IS Y-Y¹ =m(X-X¹)
WHERE M IS SLOPE
SO
EQUATION OF LINE IS Y-0={(8-0)/(3-6)}[X-6]

¶¶ Y= (-8/3)(X-6)
HERE YOU GO---- {3Y+8X-48=0}

HOPE THIS IS HELPFUL

Answer 2

To begin this problem, we need to use the two points that we are given to find the slope of the line. Slope is defined as the change in y values divided by the change in x values, or rise/run, and is represented by the variable m.

m = (y1-y2)/(x1-x2) = (8-0)/(3-6) = 8/(-3) = -8/3

Now, we can use the slope and one of the points from our given values to create an equation of the line in point-slope form.

y = m(x-h) + k, where a point on the line is (h,k)

y = -8/3(x - 3) + 8

Now, we can distribute our slope and simplify through addition.

y = -8/3x + 8 + 8

y = -8/3x + 16

Therefore, your answer is y = -8/3x + 16.

Hope this helps!