Question

What is the point-slope equation of the line with a slope 4/3 that goes through the point (-4,6)?

Answer 1

The point-slope form of the equation is y - 6 = 4/3(x + 4), which is answer B.

Explanation:

In order to find the point-slope form of any equation, start with the base form of the equation.

y - y1 = m(x - x1)

Now input the slope given as m, and the point in for x1 and y1.

y - y1 = m(x - x1)

y - 6 = 4/3(x - -4)

y - 6 = 4/3(x + 4)

Answer 2

`\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})~\hspace{10em}slope = m\implies \cfrac{4}{3}\\\\\\\begin{array}c\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-6=\cfrac{4}{3}[x-(-4)]\implies y-6=\cfrac{4}{3}(x+4)`