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Find the magnitude and direction (in degrees) of the vector. v = ‹ - sqrt(7)/9, - sqrt(2)/3 ›

User Uncletall
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1 Answer

1 vote
The magnitude is given by:
lvl = root ((- root (7) / 9) ^ 2 + (- root (2) / 3) ^ 2)
lvl = 0.555555556
The address is given by:
cos (theta) = (- root (7) / 9) / (0.555555556)
Clearing theta:
theta = acos ((- root (7) / 9) / (0.555555556))
theta = 121.95 degrees
Answer:
The magnitude and direction (in degrees) of the vector are:
lvl = 0.555555556
theta = 121.95 degrees
User Ujju
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7.2k points