Question

) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?

Answer 1

The mass % of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water is calculated as below


%(M/M) = mass of the solute(unknown salt)/ mass of the solvent(water) x 100

= 18.9 g/ 39.5 g x100 =47.85% (M/M)

Answer 2

32.4%

Step-by-step explanation:

Step 1: Given data

Mass of the solute = 18.9 g

Mass of the solvent = 39.5 g

Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g

Step 2: Calculate the mass percent of the solute in the solution

We use the following expression.

`\% m/m =(mass\ of\ the\ solute)/(mass\ of\ the\ solution) * 100\%=(18.9g)/(58.4g) * 100\% =32.4\%`