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Complete the following table.

Acid Molarity Moles of H⁺ released per liter

HCl 1 ____

H2SO4 1 ____

H3PO4 1 ____

H2SO4 0.5 ____

H3PO4 3 ____

HNO3 2 ____

User Lathspell
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2 Answers

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Complete the following table.

Acid Molarity Moles of H⁺ released per liter

HCl 1

H2SO4 1

H3PO4 1

H2SO4 0.5

H3PO4 3

HNO3 2

[Answer]

1

2

3

1

9

2

User Rossella
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Answer: see the last column in the final table of the explanation below.

Step-by-step explanation:

1) Arrange the data to understand the question:

Acid Molarity Moles of H⁺ released per liter

HCl 1 ____

H2SO4 1 ____

H3PO4 1 ____

H2SO4 0.5 ____

H3PO4 3 ____

HNO3 2 ____

2) All the given acids are strong acids, so you can consider they dissociate completely and release all the hydrogens present in the chemical formula.

3) The molarity formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters

From that, n = M×V

Go one by one with that formula.


Acid Molarity Moles of solute number of H in Moles H⁺ per liter the chemical formula per liter

HCl 1 1M×1L = 1 1 1×1 = 1

H₂SO4₄ 1 1M×1L = 1 2 2×1 = 2
H₃PO₄ 1 1M×1L = 1 3 3×1 = 3

H₂SO₄ 0.5 0.5M×1L = 0.5 2 2×0.5 = 1

H₃PO₄ 3 3M×1L = 3 3 3×3 = 9

HNO₃ 2 2M×1L = 2 2 2×2 = 4


User Mohamed Irshad
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