Question

What is the center of the circle with the equation (x-1)2 + (y-3)2= 9?

Answer 1

The values of the numbers in parentheses give the coordinates of the center

x - 1 means that x coordinate is 1 and y - 3 gives the y coordinate which is 3

Center is at ( 1, 3) answer

Answer 2

Standard form equation of the circle:


`(x-a)^2+(y-b)^2=r^2`


`\text{a and b are the x and y coordinates of the center of the circle; r is a length of a radius}`

We have:

`(x-1)^2+(y-3)^2=9\\\\\text{therefore coordinates of the center of the circle are (1; 3) and a radius is equal 3}`