Let x and y be width and length of the plot to be fenced. Therefore,
Area (A) = xy m^2
If the side bordering the river is x, then
Circumference (C) = 8500 = x+2y => x = 8500-2y
Substituting for w in the equation for A;
A = (8500-2y)y = 8500y -2y^2
For maximum area, derivative of A with respect to y is 0. That is;
dA/dy = 0 = 8500 -4y => 4y = 8500 => y = 8500/4 = 2125 m
And, x = 8500-2y = 8500 -2*2125 = 4250 m
Therefore,
One side = 4,250 m and second side = 2,125 m.
Largest area, A = 4250*2125 = 9,031,250 m^2