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Mike has attempted 84 free throws. Of those attempted, 63 have gone in the basket. Based on this rate, what is the probability that Mike's next free throw attempt will go in the basket?

1 Answer

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Answer :P(\text{ Mike's next free throw attempt will go in the basket })= 0.75

Step-by-step explanation:

Since we have given that ,

Total number of free throws Mike has =84

Number of free throws have gone in the basket = 63

As we know that


P(\text{ Mike's next free throw attempt will go in the basket})= \frac{\text{Number of favourable outcome}}{\text{Total number of outcomes}}


P(\text{ Mike's next free throw attempt will go in the basket })= (63)/(84)


P(\text{ Mike's next free throw attempt will go in the basket })= 0.75


User Dmytro Yashkir
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