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What is the surface area of the regular pyramid

What is the surface area of the regular pyramid-example-1
User Mstef
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The total area is the sum of the area of the base (65 m^2) and six times the area of one of the triangular sides.  This area (of one side) is (1/2)(base)(height), or (1/2)(5)(12), so the total area of the sides is 6(1/2)(5)(12) = 180 m^2.  Thus, the total area is 65 m^2 + 180 m^2 = 245 m^2.
User Loreto
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