Question

A runner is participating in a 10.3 mile race. If the runner stopped at a water station that is twice as far from the starting line as from the finish​ line, how far is the runner from the finish​ line?

Answer 1

6.86

Explanation:

Answer 2

We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:


`d = 10.3mi = d_(1)+ d_(2)`

We know that there is a water station that is twice as far from the starting line as from the finish​ line, then:


`d_(2)=2d_(1)`

So:


`d_(1) +2d_(1)=10.3`
∴
`d_(1)=3.43mi`

and
`d_(2)=2(3.43)=6.86mi`

Finally, the distance of the runner from the finish​ line is:


`6.86mi`