Question

) how much of a 0.225 m kcl solution contains 55.8 g kcl?

Answer 1

Answer : The volume of solution is, 3.33 liter

Explanation : Given,

Mass of KCl = 55.8 g

Molar mass of KCl = 74.5 g/mole

Molarity = 0.225 M

Molarity : It is defined as the number of moles of solute present in one liter of solution.

In this question, the solute is KCl.

Formula used :

`Molarity=(w_b)/(M_b* V)`

where,

`w_b` = mass of solute KCl

`M_b` = molar mass of solute KCl

V = volume of solution = ?

Now put all the given values in the above formula, we get the molarity of the solution.

`0.225mole/L=(55.8g)/(74.5g/mole* V)`

`V=3.33L`

Therefore, the volume of solution is, 3.33 liter

Answer 2

The amount of a 0.225 M KCl solution that contain 55.8 g KCl is calculated as below

calculate the moles of KCl =mass/ molar mass

=55.8 g/74.5 g/mol = 0.749 moles

volume of KCl = moles/molarity

= 0.749/0.225 = 3.329 liters of KCl