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A stock solution of naoh is 0.800 m. what volume of this solution (in ml) is needed to prepare 2.00 l of 0.342 m naoh?

User Jpihl
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The volume of the solution(in Ml) needed to prepare 2.00 L of 0.342 M NaOH is calculated using the below formula

M1V1 =M2V2
M1=0.800 M
V1=?
M2=0.342 m
V2= 2.00 L

by making V1 the subject of the formula = M2V2/M1

= 2.00 L x 0.342/ 0.800 =0.855 L stock solution is neede


User Maybel
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