Question

What is the mass occupied by 44.8 l of nitrogen (n2​)​ at standard​ conditions?

Answer 1

Data Given:
Volume = V = 44.8 L

Standard Pressure = P = 1 atm

Standard Temperature = T = 273 K

According to Ideal Gas Equation,

P V = n R T

Solving for n,

n = P V / R T

Putting values,

n = (1 atm × 44.8 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)

n = 1.99 mol

Now, calculating for mass,

n = Mass / M.mass
Or,
Mass = n × M.mass

Mass = 1.99 mol × 28 g.mol⁻¹

Mass = 55.72 grams