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Find the third derivative of f at x = 0 if the Maclaurin series for f(x) = 1 - 9x + 16x2 - 25x3 + …

User Grapkulec
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The third derivative for the sequence will be:
f(x)=1-9x+16x^2-25x^3
first derivative
f'(x)=-9+32x-75x^2
second derivative
f"(x)=32x-150x
Third derivative:
f"'(x)=-150

Answer: f'''(x)=-150

User Graeme Perrow
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8.2k points
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