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How many atoms of each element are needed to create an ionic compound of strontium selenide

1 Answer

7 votes
Step 1:
Calculate the ionic charges on both atoms:

As Strontium belongs to Group-II in periodic table so it will tend to loose two electrons and form Sr⁺² , i.e.

Sr → Sr⁺² + 2 e⁻

While, Se belonging to Group-VI will tend to gain two electrons and form Se⁻², i.e.

Se + 2 e⁻ → Se⁻²

Step 2:
Multiply the coefficient of each element by the charge of other element.

Se⁻² × 2 = 2 Se⁻² ∴ where 2 is charge on Sr
And,
Sr⁺² × 2 = 2 Sr⁺² ∴ where 2 is charge on Se

So, the formula comes out to be,

Sr₂Se₂

Or divide both coefficients by 2 to have a simplest form. i.e...

SrSe

Result:
One One atoms of each element are needed to create an ionic compound of Strontium Selenide.
User Dean Chiu
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