Question

The probability of picking two black marbles from a box at random without replacement is 1091 . The probability of drawing a black marble first is 514 . What is the probability of picking a second black marble, given that the first marble picked was black?

Answer 1

The probability of picking a second black marble, given that the first marble picked was black, is 1.

Step-by-step explanation:

To find the probability of picking a second black marble, given that the first marble picked was black, we can use the formula for conditional probability: P(A|B) = P(A and B)/P(B).

In this case, A represents the event of picking a black marble on the second draw, and B represents the event of picking a black marble on the first draw.

We are given that P(B) = 514, and the probability of picking two black marbles without replacement is 1091. Therefore, P(A and B) = P(A|B) * P(B) = (1091/514) * (514/1091) = 1.

So, the probability of picking a second black marble, given that the first marble picked was black, is 1.

Answer 2

The correct answer to the question above is 4/13. Below it shows how it's achieved...

EQUATION:
P(A|B) = P(A ∩ B)
P(B)

Step 1: Identify
P(B) = 5/14
P(A ∩ B) = 10/91

Step 2: Insert into the equation and Solve
10/91 ÷ 5/14
Use reciprocal to divide
10/91 × 14/5
Simplify the answer
140/455
Simplified (Final Answer)
4/13