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What is the sum of a geometric sequence 1, 3, 9, ... if there are 12 terms? A. 292,524 B. 265,720 C. 139,968 D. 104,976
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What is the sum of a geometric sequence 1, 3, 9, ... if there are 12 terms? A. 292,524 B. 265,720 C. 139,968 D. 104,976
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Feb 26, 2019
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What is the sum of a geometric sequence 1, 3, 9, ... if there are 12 terms?
A. 292,524
B. 265,720
C. 139,968
D. 104,976
Mathematics
high-school
Vishal G
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Vishal G
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we know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
common ration r is equal to 3
number of terms n is 12
The
Sum of geometric series is given by the formula
Sum=a1*[1-r
^n]/[1-r]
Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
Sum=531440/2-----> 265720
the answer is
265720
Rach
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Mar 4, 2019
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Rach
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