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Why are the values for sine and cosine equal at 45°?

User Salivan
by
8.4k points

2 Answers

4 votes

Answer:

The complement of
45\degree is
45\degree.

Explanation:

Method 1

From the isosceles right triangle; See diagram in attachment.


\sin(45\degree)=(x)/(x√(2) )



\sin(45\degree)=(1)/(√(2) )



\sin(45\degree)=(√(2))/(2 )


Also;



\sin(45\degree)=(x)/(x√(2) )



\cos(45\degree)=(1)/(√(2) )



\cos(45\degree)=(√(2))/(2 )

Hence;


\cos(45\degree)=\sin(45\degree)


Method 2


\sin(45\degree)=\cos(45\degree) because the complement of
45\degree is still
45\degree.


Complementary angles add to
90\degree.

In general if we have an angle
\theta, then its complement is
(90-\theta)\degree.

There is a relationship between the sine of an angle,
\theta and the cosine of its complement,(90-\theta)\degree[/tex].


The relationship is that,


\sin(\theta \degree)=\cos((90-\theta)\degree).


If
\theta=45\degree, then



\sin(45 \degree)=\cos((90-45)\degree).



\Rightarrow \sin(45\degree)=\cos(45\degree).


Why are the values for sine and cosine equal at 45°?-example-1
User Sebdesign
by
8.2k points
2 votes
For this case we have a rectangle triangle.
The opposite leg is the sine of the angle.
The adjacent catheto is the cosine of the angle.
For 45 degrees, the length of both legs is the same.
Thus,
Sine (45) = Cosine (45)
Answer:
The length of the legs is the same for a 45 degree angle.
User RafaelTSCS
by
8.3k points