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describe the steps you would use to factor 2x ^ 3 + 5x ^ 2 - 8x - 20 completely then State the factored form. this isn't multiple choice btw

User Sembrano
by
7.9k points

2 Answers

1 vote

Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0


You see that the term will be 0 for x = 2


(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0


You can use the abc-formula to solve the quadratic equation.


x = -2.5 ∨ x = -2


So the factored form will be


2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


User Bhargav Jhaveri
by
7.3k points
2 votes

Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0

You see that the term will be 0 for x = 2

(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0

You can use the abc-formula to solve the quadratic equation.

x = -2.5 ∨ x = -2

So the factored form will be

2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


User Amica
by
8.6k points

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